Optimal. Leaf size=205 \[ -\frac{a^3 (A-B)}{64 d (a \sin (c+d x)+a)^4}+\frac{a^2 (A+B)}{96 d (a-a \sin (c+d x))^3}-\frac{a^2 (2 A-B)}{48 d (a \sin (c+d x)+a)^3}+\frac{a (5 A+3 B)}{128 d (a-a \sin (c+d x))^2}-\frac{a (5 A-B)}{64 d (a \sin (c+d x)+a)^2}+\frac{5 (3 A+B)}{128 d (a-a \sin (c+d x))}+\frac{5 (7 A+B) \tanh ^{-1}(\sin (c+d x))}{128 a d}-\frac{5 A}{32 d (a \sin (c+d x)+a)} \]
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Rubi [A] time = 0.248532, antiderivative size = 205, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.097, Rules used = {2836, 77, 206} \[ -\frac{a^3 (A-B)}{64 d (a \sin (c+d x)+a)^4}+\frac{a^2 (A+B)}{96 d (a-a \sin (c+d x))^3}-\frac{a^2 (2 A-B)}{48 d (a \sin (c+d x)+a)^3}+\frac{a (5 A+3 B)}{128 d (a-a \sin (c+d x))^2}-\frac{a (5 A-B)}{64 d (a \sin (c+d x)+a)^2}+\frac{5 (3 A+B)}{128 d (a-a \sin (c+d x))}+\frac{5 (7 A+B) \tanh ^{-1}(\sin (c+d x))}{128 a d}-\frac{5 A}{32 d (a \sin (c+d x)+a)} \]
Antiderivative was successfully verified.
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Rule 2836
Rule 77
Rule 206
Rubi steps
\begin{align*} \int \frac{\sec ^7(c+d x) (A+B \sin (c+d x))}{a+a \sin (c+d x)} \, dx &=\frac{a^7 \operatorname{Subst}\left (\int \frac{A+\frac{B x}{a}}{(a-x)^4 (a+x)^5} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^7 \operatorname{Subst}\left (\int \left (\frac{A+B}{32 a^5 (a-x)^4}+\frac{5 A+3 B}{64 a^6 (a-x)^3}+\frac{5 (3 A+B)}{128 a^7 (a-x)^2}+\frac{A-B}{16 a^4 (a+x)^5}+\frac{2 A-B}{16 a^5 (a+x)^4}+\frac{5 A-B}{32 a^6 (a+x)^3}+\frac{5 A}{32 a^7 (a+x)^2}+\frac{5 (7 A+B)}{128 a^7 \left (a^2-x^2\right )}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^2 (A+B)}{96 d (a-a \sin (c+d x))^3}+\frac{a (5 A+3 B)}{128 d (a-a \sin (c+d x))^2}+\frac{5 (3 A+B)}{128 d (a-a \sin (c+d x))}-\frac{a^3 (A-B)}{64 d (a+a \sin (c+d x))^4}-\frac{a^2 (2 A-B)}{48 d (a+a \sin (c+d x))^3}-\frac{a (5 A-B)}{64 d (a+a \sin (c+d x))^2}-\frac{5 A}{32 d (a+a \sin (c+d x))}+\frac{(5 (7 A+B)) \operatorname{Subst}\left (\int \frac{1}{a^2-x^2} \, dx,x,a \sin (c+d x)\right )}{128 d}\\ &=\frac{5 (7 A+B) \tanh ^{-1}(\sin (c+d x))}{128 a d}+\frac{a^2 (A+B)}{96 d (a-a \sin (c+d x))^3}+\frac{a (5 A+3 B)}{128 d (a-a \sin (c+d x))^2}+\frac{5 (3 A+B)}{128 d (a-a \sin (c+d x))}-\frac{a^3 (A-B)}{64 d (a+a \sin (c+d x))^4}-\frac{a^2 (2 A-B)}{48 d (a+a \sin (c+d x))^3}-\frac{a (5 A-B)}{64 d (a+a \sin (c+d x))^2}-\frac{5 A}{32 d (a+a \sin (c+d x))}\\ \end{align*}
Mathematica [A] time = 0.836141, size = 142, normalized size = 0.69 \[ \frac{\frac{-15 (7 A+B) \sin ^6(c+d x)-15 (7 A+B) \sin ^5(c+d x)+40 (7 A+B) \sin ^4(c+d x)+40 (7 A+B) \sin ^3(c+d x)-33 (7 A+B) \sin ^2(c+d x)-33 (7 A+B) \sin (c+d x)+48 (A-B)}{(\sin (c+d x)-1)^3 (\sin (c+d x)+1)^4}+15 (7 A+B) \tanh ^{-1}(\sin (c+d x))}{384 a d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.109, size = 321, normalized size = 1.6 \begin{align*} -{\frac{35\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) A}{256\,da}}-{\frac{5\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) B}{256\,da}}+{\frac{5\,A}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}+{\frac{3\,B}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}-{\frac{A}{96\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{3}}}-{\frac{B}{96\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{3}}}-{\frac{15\,A}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) }}-{\frac{5\,B}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) }}-{\frac{5\,A}{32\,da \left ( 1+\sin \left ( dx+c \right ) \right ) }}-{\frac{A}{64\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}+{\frac{B}{64\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}-{\frac{A}{24\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}+{\frac{B}{48\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}-{\frac{5\,A}{64\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{2}}}+{\frac{B}{64\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{2}}}+{\frac{35\,\ln \left ( 1+\sin \left ( dx+c \right ) \right ) A}{256\,da}}+{\frac{5\,\ln \left ( 1+\sin \left ( dx+c \right ) \right ) B}{256\,da}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.05065, size = 297, normalized size = 1.45 \begin{align*} \frac{\frac{15 \,{\left (7 \, A + B\right )} \log \left (\sin \left (d x + c\right ) + 1\right )}{a} - \frac{15 \,{\left (7 \, A + B\right )} \log \left (\sin \left (d x + c\right ) - 1\right )}{a} - \frac{2 \,{\left (15 \,{\left (7 \, A + B\right )} \sin \left (d x + c\right )^{6} + 15 \,{\left (7 \, A + B\right )} \sin \left (d x + c\right )^{5} - 40 \,{\left (7 \, A + B\right )} \sin \left (d x + c\right )^{4} - 40 \,{\left (7 \, A + B\right )} \sin \left (d x + c\right )^{3} + 33 \,{\left (7 \, A + B\right )} \sin \left (d x + c\right )^{2} + 33 \,{\left (7 \, A + B\right )} \sin \left (d x + c\right ) - 48 \, A + 48 \, B\right )}}{a \sin \left (d x + c\right )^{7} + a \sin \left (d x + c\right )^{6} - 3 \, a \sin \left (d x + c\right )^{5} - 3 \, a \sin \left (d x + c\right )^{4} + 3 \, a \sin \left (d x + c\right )^{3} + 3 \, a \sin \left (d x + c\right )^{2} - a \sin \left (d x + c\right ) - a}}{768 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.60582, size = 602, normalized size = 2.94 \begin{align*} -\frac{30 \,{\left (7 \, A + B\right )} \cos \left (d x + c\right )^{6} - 10 \,{\left (7 \, A + B\right )} \cos \left (d x + c\right )^{4} - 4 \,{\left (7 \, A + B\right )} \cos \left (d x + c\right )^{2} - 15 \,{\left ({\left (7 \, A + B\right )} \cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) +{\left (7 \, A + B\right )} \cos \left (d x + c\right )^{6}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \,{\left ({\left (7 \, A + B\right )} \cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) +{\left (7 \, A + B\right )} \cos \left (d x + c\right )^{6}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \,{\left (15 \,{\left (7 \, A + B\right )} \cos \left (d x + c\right )^{4} + 10 \,{\left (7 \, A + B\right )} \cos \left (d x + c\right )^{2} + 56 \, A + 8 \, B\right )} \sin \left (d x + c\right ) - 16 \, A - 112 \, B}{768 \,{\left (a d \cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) + a d \cos \left (d x + c\right )^{6}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.43809, size = 319, normalized size = 1.56 \begin{align*} \frac{\frac{60 \,{\left (7 \, A + B\right )} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a} - \frac{60 \,{\left (7 \, A + B\right )} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a} + \frac{2 \,{\left (385 \, A \sin \left (d x + c\right )^{3} + 55 \, B \sin \left (d x + c\right )^{3} - 1335 \, A \sin \left (d x + c\right )^{2} - 225 \, B \sin \left (d x + c\right )^{2} + 1575 \, A \sin \left (d x + c\right ) + 321 \, B \sin \left (d x + c\right ) - 641 \, A - 167 \, B\right )}}{a{\left (\sin \left (d x + c\right ) - 1\right )}^{3}} - \frac{875 \, A \sin \left (d x + c\right )^{4} + 125 \, B \sin \left (d x + c\right )^{4} + 3980 \, A \sin \left (d x + c\right )^{3} + 500 \, B \sin \left (d x + c\right )^{3} + 6930 \, A \sin \left (d x + c\right )^{2} + 702 \, B \sin \left (d x + c\right )^{2} + 5548 \, A \sin \left (d x + c\right ) + 340 \, B \sin \left (d x + c\right ) + 1771 \, A - 35 \, B}{a{\left (\sin \left (d x + c\right ) + 1\right )}^{4}}}{3072 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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